-12x^2+10x+42=0

Solution for -12x^2+10x+42=0 equation:

-12x^2+10x+42=0

a = -12; b = 10; c = +42;
Δ = b2-4ac
Δ = 102-4·(-12)·42
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-46}{2*-12}=\frac{-56}{-24}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+46}{2*-12}=\frac{36}{-24}
=-1+1/2
$